(X-3)^2+(y+4)^2=16

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Solution for (X-3)^2+(y+4)^2=16 equation: 



(X-3)^2+(X+4)^2=16

We move all terms to the left:

(X-3)^2+(X+4)^2-(16)=0

We move all terms containing X to the left, all other terms to the right

(X-3)^2+(X+4)^2=16

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